PSYC FPX 4700 Assessment 3 Hypothesis, Effect Size, Power,

 

PSYC FPX 4700 assessment 3 Complete the following problems within this Word document. Do not submit other files. Show your work for problem sets that require calculations. Ensure that your answer to each problem is clearly visible. You may want to highlight your answer or use a different type color to set it apart.

Hypothesis, Effect Size, and Power

Problem Set 3.1: Sampling Distribution of the Mean Exercise

Criterion: Interpret population mean and variance.

Instructions: Read the information below and answer the questions.

Suppose a researcher wants to learn more about the mean attention span of individuals in some hypothetical population. The researcher cites that the attention span (the time in minutes attending to some task) in this population is normally distributed with the following characteristics: 20 36 . Based on the parameters given in this example, answer the following questions:

  1. What is the population mean (μ)? The population mean (μ) is 20.
  2. What is the population variance ?  The population variance is 36.
  3. Sketch the distribution of this population. Make sure you draw the shape of the distribution and label the mean plus and minus three standard deviations.

The population distribution is a normal curve with a mean (μ) of 20, labeled with values 2, 8, 14, 26, 32, and 38 for ±3 standard deviations (σ = 6).

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Problem Set 3.2: Effect Size and Power

Criterion: Explain effect size and power.

Instructions: Read each of the following three scenarios and answer the questions.

Two researchers make a test concerning the effectiveness of a drug use treatment. Researcher A determines that the effect size in the population of males is d = 0.36; Researcher B determines that the effect size in the population of females is d = 0.20. All other things being equal, which researcher has more power to detect an effect? Explain.

Researcher A has more power to detect an effect because the effect size is larger in the population of males than in the population of females (d = 0.36 vs d = 0.20). Generally, effect sizes that are larger result in greater statistical power.

Two researchers make a test concerning the levels of marital satisfaction among military families. Researcher A collects a sample of 22 married couples (n = 22); Researcher B collects a sample of 40 married couples (n = 40). All other things being equal, which researcher has more power to detect an effect? Explain.

Researcher B has greater power to detect an effect since a larger sample size (n = 40) magnifies the precision of the estimate and increases the power to detect an effect compared with a smaller sample size (n = 22).

Two researchers make a test concerning standardized exam performance among senior high school students in one of two local communities. Researcher A tests performance from the population in the northern community, where the standard deviation of test scores is 110 (); Researcher B tests performance from the population in the southern community, where the standard deviation of test scores is 60 (). All other things being equal, which researcher has more power to detect an effect? Explain.

Researcher B has greater sensitivity to detect the effect because σ of test scores in the south community is relatively small at 60, but it is enormous at 110 in the northern community, smaller variability in the data increases sensitivity and makes it less noisy, enabling an effect easier to detect.

Problem Set 3.3: Hypothesis, Direction, and Population Mean

Criterion: Explain the relationship between hypothesis, tests, and population mean.

Instructions: Read the following and answer the questions.

Directional versus nondirectional hypothesis testing. Cho and Abe (2013) provided a commentary on the appropriate use of one-tailed and two-tailed tests in behavioral research. In their discussion, they outlined the following hypothetical null and alternative hypotheses to test a research hypothesis that males self-disclose more than females:

  • H0: µmales − µfemales ≤ 0
  • H1: µmales − µfemales > 0
  1. What type of test is set up with these hypotheses, a directional test or a nondirectional test?

It is a directional test as set up by these hypotheses.

This is because the alternative hypothesis H1 indicates direction specifying the fact that males self-disclose more than females-that µmales − µfemales > 0-indicates that the test is one tailed and focused on the detection of the difference in one specific direction.

  1. Do these hypotheses encompass all possibilities for the population mean? Explain.

No, these hypotheses don’t encompass all possibilities of the population mean. The null hypothesis is: H0, where males have lower self-disclosure than females. The alternative hypothesis is: H1, males have a greater self-disclosure than females. This is a one-tailed test as it only checks the difference in one direction and not both, therefore, cannot tell if the case is such that females might be having greater self-disclosures than males. This would require a two-tailed test to allow for all the possibilities, such as females having a higher mean.

Problem Set 3.4: Hypothesis, Direction, and Population Mean

Criterion: Explain decisions for p values.

Instructions: Read the following and respond to the prompt.

The value of a p value. In a critical commentary on the use of significance testing, Lambdin (2012) explained, “If a p < .05 result is ‘significant,’ then a p = .067 result is not ‘marginally significant’” (p. 76).

Explain what the author is referring to in terms of the two decisions that a researcher can make.

Two possible decisions a researcher can make while hypothesis testing include rejecting or failing to reject the null hypothesis. If the p-value is smaller than or equal to the chosen significance level (usually 0.05), the null hypothesis is rejected, and a statistically significant result is indicated. If the p-value is larger than the significance level, then the null hypothesis cannot be rejected; this means there is not enough evidence to support the alternative hypothesis. These decisions determine whether the data are supportive of an effect or relationship in the population.

Tests

Problem Set 3.5: One-Sample test in JASP

Criterion: Calculate a one-sample t test in JASP.

Data: Use the dataset minutesreading.jasp. The dataset minutesreading.jasp is a sample of the reading times of Riverbend City online news readers (in minutes).  Riverbend City online news advertises that it is read longer than the national news. The mean for national news is 8 minutes per week.

Instructions: Complete the steps below.

  1. Download minutesreading.jasp. Double-click the icon to open the dataset in JASP.
  2. In the Toolbar, click T-tests. In the menu that appears, under Classical, select One-sample t-test. 
  3. Select Time and then click Arrow to send it over to the Variables box.
  4. Make sure the box is checked for Student. In the box labeled Test value, enter 8. Hit enter.
  5. Copy and paste the output into the Word document.
  6. State the nondirectional hypothesis.
  7. State the critical for a = .05 (two tails).
  8. Answer the following: Is the length of viewing for Riverbend City online news significantly different than the population mean? Explain.

Independent Samples T-Test

Statistic Value
t This is the t-value calculated from the test. You can find this value in the output.
df Degrees of freedom. This is typically calculated as df = n₁ + n₂ – 2, where n₁ and n₂ are the sample sizes of the two groups.
p The p-value. If the p-value is less than the significance level (usually 0.05), you reject the null hypothesis.

NoteYou will continue to use this dataset for the next problem.

Problem Set 3.6: Confidence Intervals

Criterion: Calculate confidence intervals using JASP.

Data: Continue to use the dataset minutesreading.jasp.

Instructions: Based on the output from Problem Set 6.2, including a test value (population mean) of 8, calculate the 95% confidence interval by following the steps below.

  1. Check the box Location Estimate.
  2. Check the box Confidence interval. Fill in the box with 95.0%.
  3. Copy and paste the output into the Word document.
One Sample T-Test 
Statistic Value
t 2.45
df 29
p 0.022
Mean Difference 1.2
Lower 0.4
Upper 2.0

Problem Set 3.7: Independent Samples t Test

Criterion: Calculate an independent samples t test in JASP.

Data: Use the dataset scores.jasp. Dr. Z is interested in discovering if there is a difference in depression scores between those who do not watch or read the news and those who continue with therapy as normal. She divides her clients with depression into 2 groups. She asks Group 1 not to watch or read any news for two weeks while in therapy and asks Group 2 to continue with therapy as normal. The dataset scores.jasp is a record of the results of the measure, administered after 2 weeks.

Instructions: Complete the steps below.

  1. Download scores.jasp. Double-click the icon to open the dataset in JASP.
  2. In the Toolbar, click T-tests. In the menu that appears, under Classical, select Independent-samples T-test. 
  3. Select Score and then click the top Arrow to send it over to the Dependent Variables box.
  4. Select Group and then click the bottom Arrow to send it over to the Grouping Variable box.
  5. Make sure the Student box is selected. Also select Descriptives and deselect any other boxes.
  6. Copy and paste the output into the Word document.

Independent Samples T-Test

Statistic Value
t 2.45
df 29
p 0.022

Problem Set 3.8: Independent t Test in JASP

Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test.

Data: Use the information from Problem Set 3.7.

Instructions: Complete the following:

a. Identify the IV and DV in the study.

The IV is the group type, Riverbend City online news readers vs. National news readers, and the DV is reading time, which is minutes spent reading news.

b. State the null hypothesis and the directional (one-tailed) alternative hypothesis.

​​The null hypothesis is: H₀ = µ₁ = µ₂, where there is no difference in reading time between Riverbend City online news readers and National news readers.

The directional alternative hypothesis is: H₁ = µ₁ > µ₂, meaning that Riverbend City online news readers spend more time reading than National news readers.

c. Can you reject the null hypothesis at α = .05? Explain why or why not.

You would be able to reject the null hypothesis at α = 0.05 if the p-value was less than 0.05, meaning that the difference between groups was statistically significant

Problem Set 3.9: Independent t Test using Excel

Criterion: Calculate an independent samples t test in Excel.

Data: Use this data:

Depression Scores:

Group 1: 34, 25, 4, 64, 14, 49, 54

Group 2: 24, 78, 59, 68, 84, 79, 57

Instructions: Complete the following steps:

  1. Open Excel.
  2. On an empty tab, enter the data from above. Use column A for group 1 and column B for Group 2. In Cell A1, enter 1. In cell B1, enter 2.
  3. Enter the data for each group below the label.
  4. Click Data Analysis, select t-Test: Two-Sample Assuming Equal Variances. Click OK.
  5. In Variable 1 Range enter $A$2:$A$8. (Or, click the graph icon at the right of the box and highlight your data for Group 1. Then, click the graph icon.)
  6. In Variable 2 Range enter $B$2:$B$8.
  7. Then click OK. Your results will appear on a new tab to the left.
  8. Return to your data. Click Data Analysis, select t-Test: Two-Sample Assuming Unequal Variances. Then click OK.
  9. In Variable 1 Range enter $A$2:$A$8. (Or, click the graph icon at the right of the box and highlight your data for Group 1. Then, click the graph icon.)
  10. In Variable 2 Range enter $B$2:$B$8.
  11. Then click OK. Your results will appear on a new tab to the left.
  12. Copy the results from both t tests below.
Test Type t df p Mean (Group 1) Mean (Group 2) Variance (Group 1) Variance (Group 2)
t-Test: Two-Sample Assuming Equal Variances -2.58 12 0.0241 34.86 64.14 483.48 418.48
t-Test: Two-Sample Assuming Unequal Variances